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@json-q json-q commented Sep 15, 2025

[English Template / 英文模板]

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🔗 相关 Issue

💡 需求背景和解决方案

控件的 button 元素应该有 type=button,避免祖先元素存在 form 时触发 form 的默认行为

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🇺🇸 英文
🇨🇳 中文

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changeset-bot bot commented Sep 15, 2025

⚠️ No Changeset found

Latest commit: 955f078

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Summary of Changes

Hello @json-q, I'm Gemini Code Assist1! I'm currently reviewing this pull request and will post my feedback shortly. In the meantime, here's a summary to help you and other reviewers quickly get up to speed!

This pull request addresses a potential issue where control buttons, when inadvertently placed within an HTML form, could trigger an unwanted form submission. By explicitly setting the type attribute of these buttons to button, the change ensures they behave as intended, preventing unintended side effects and improving the robustness of the UI components.

Highlights

  • HTML Button Type: Explicitly set the type attribute of control button elements to button to prevent default form submission behavior when nested within a form.
  • ButtonControl Update: The createButton method in buttonControl.ts now ensures that created buttons have type="button".
  • Swipe Control Update: The button within the Swipe control in swipe.ts is now explicitly assigned type="button".
  • Zoom Control Update: Buttons created by the Zoom control in zoom.ts are now correctly assigned type="button".
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Code Review

本次 PR 旨在为控件中的按钮元素添加 type='button',以防止意外的表单提交行为。这些更改在方向上是正确的。我发现了一些可以改进的地方:一处是轻微的代码简化,另一处是 zoom.ts 中一个比较严重的类型问题,一个 <button> 元素被错误地转换为了 HTMLLinkElement 类型。详情请见具体的审查评论。

Comment on lines 121 to +122
const link = DOM.create('button', className, container) as HTMLLinkElement;
link.type = 'button';

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high

这里存在一个类型问题。创建的元素是 <button>,因此应该转换为 HTMLButtonElement,而不是 HTMLLinkElementHTMLLinkElement 是用于 <link> 标签的,其 type 属性的含义也不同。此外,变量名 link 具有误导性,建议修改为 button 以提高代码清晰度。

Suggested change
const link = DOM.create('button', className, container) as HTMLLinkElement;
link.type = 'button';
const link = DOM.create('button', className, container) as HTMLButtonElement;
link.type = 'button';

return DOM.create('button', `l7-button-control ${className}`) as HTMLElement;
const btn = DOM.create('button', `l7-button-control ${className}`) as HTMLButtonElement;
btn.type = 'button';
return btn as HTMLElement;

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medium

这里的 as HTMLElement 类型断言是多余的。HTMLButtonElementHTMLElement 的子类型,因此可以直接返回,无需强制类型转换。

Suggested change
return btn as HTMLElement;
return btn;

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